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| Date: | Thu, 05 Jul 2001 15:00:44 -0700 |
| To: | "Karr, David" <david DOT karr AT cacheflow DOT com>, |
| "'cygwin AT cygwin DOT com'" <cygwin AT cygwin DOT com> | |
| From: | Randall R Schulz <rrschulz AT cris DOT com> |
| Subject: | Re: Pipe "make" stdout and stderr to process? |
| In-Reply-To: | <2C08D4EECBDED41184BB00D0B74733420473EDEE@exchanger.cachefl |
| ow.com> | |
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David,
It's somewhat counterintuitive by comparison to the ordering required in
the absence of a pipe, but you have to merge stderr (2) into stdout (1)
before the pipe symbol:
make 2>&1 |filterprog
Randall Schulz
At 14:13 2001-07-05, Karr, David wrote:
>How do I run "make" so I can pass both stdout and stderr to a filtering
>process? I'm familiar with writing the output to a file, taking both stdout
>and stderr ("make > make.out 2>&1"), but I don't see how to get this to work
>if I just want to pipe the output (both stdout and stderr) to another
>process. When I do "make | filterprog 2>&1", it seems to have no effect, in
>that it appears as if the stderr from "make" goes directly to the console.
> >From reading the "bash" man page, it almost seems as if redirection doesn't
>apply to piping.
>
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