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From:	"Jeff Hu" <max AT huville DOT com>
To:	<cygwin AT sources DOT redhat DOT com>
Subject:	RE: Starting Programms in the background
Date:	Thu, 2 Nov 2000 19:46:36 -0500
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I think this is related to how bash is started. If you:

1) start a dos box window
2) start bash
3) start notepad in the background
4) exit bash
5) exit the dos prompt window

the dos box remains until you exit notepad.

Jeff
-----Original Message-----
From: cygwin-owner AT sources DOT redhat DOT com
[mailto:cygwin-owner AT sources DOT redhat DOT com]On Behalf Of Christopher Faylor
Sent: Thursday, November 02, 2000 3:20 PM
To: cygwin AT sources DOT redhat DOT com
Subject: Re: Starting Programms in the background

On Thu, Nov 02, 2000 at 11:58:01AM -0800, Earnie Boyd wrote:
>--- Christopher Faylor <cgf AT redhat DOT com> wrote:
>> On Thu, Nov 02, 2000 at 06:10:07AM +0100, klaus DOT berndl AT sdm DOT de wrote:
>> >If i start a program in the background from bash (e.g.  "winword.exe
>> ><document> &") then all is working fine.  But if i try to exit from the
>> >bash-shell from which i have started the program before i have finished
>> >the program then bash writes "logout" but doesn?t terminate until i
>> >terminate all previous started programs.
>> >
>> >How can this be avoided, means how to exit bash regardless of any still
>> >running background programs?
>>
>> The only time this should happen is when you are using CYGWIN=tty.  In
this
>> case, the main process (bash) "owns" the tty and can't exit until every
>> child which is using the tty has exited.  The only way around this is to
>> not use CYGWIN=tty.
>>
>
>Then it's broken.  I assume notty is still the default, correct?  Then the
>window refuses to close until I exit the process.  This is with
1.1.6(0.29/3/2)
>build.

Feel free to debug it.  This exits for me on Windows NT.

cgf

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