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From: | Chris Faylor <cgf AT cygnus DOT com> |
Date: | Fri, 28 Jul 2000 12:57:49 -0400 |
To: | cygwin AT sourceware DOT cygnus DOT com |
Subject: | Re: shell script bug |
Message-ID: | <20000728125749.A5152@cygnus.com> |
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In-Reply-To: | <20000728163013.15552.qmail@web1306.mail.yahoo.com>; from yap_noel@yahoo.com on Fri, Jul 28, 2000 at 09:30:13AM -0700 |
On Fri, Jul 28, 2000 at 09:30:13AM -0700, Noel Yap wrote: >I have the following script asdf.sh: >#!/bin/sh > >if [ $# = 1 ] >then > for v in "$@" > do > echo $# should be 1 > echo "$v" > done >else > for v in "$@" > do > echo $# isn\'t be 1 > ./asdf.sh "$v" > done >fi > >Under bash, the output of the script is: >5 isn't 1 >5 isn't 1 >5 isn't 1 >5 isn't 1 >5 isn't 1 > >Under sh, there is no output. ...which is what I'd expect. I tried this on a couple of machines and the behavior is inconsistent. Some print "0 isn't be 1" (sic) and some print nothing. I would consider the triggering of the for-loop when there are no arguments supplied to the shell script to be a bug. cgf -- Want to unsubscribe from this list? Send a message to cygwin-unsubscribe AT sourceware DOT cygnus DOT com
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