X-Authentication-Warning: delorie.com: mail set sender to geda-user-bounces using -f X-Recipient: geda-user AT delorie DOT com Date: Tue, 18 Dec 2012 15:24:19 +0100 (CET) X-X-Sender: igor2 AT igor2priv To: "geda-user AT delorie DOT com" X-Debug: to=geda-user AT delorie DOT com from="gedau AT igor2 DOT repo DOT hu" From: gedau AT igor2 DOT repo DOT hu Subject: RE: [geda-user] Find rat lines - summary In-Reply-To: <7401652465A13245B1C94ECDC9747C118F80613798@wr3.warrenrogersassociates.com> Message-ID: References: <20121204183305 DOT 6b04c0dc AT jive DOT levalinux DOT org> <20121208112649 DOT 388a9d22 AT jive DOT levalinux DOT org> <1355011808 DOT 19390 DOT 8 DOT camel AT localhost> <7401652465A13245B1C94ECDC9747C118F80613798 AT wr3 DOT warrenrogersassociates DOT com> User-Agent: Alpine 2.00 (DEB 1167 2008-08-23) MIME-Version: 1.0 Content-Type: TEXT/PLAIN; charset=US-ASCII; format=flowed Reply-To: geda-user AT delorie DOT com Errors-To: nobody AT delorie DOT com X-Mailing-List: geda-user AT delorie DOT com X-Unsubscribes-To: listserv AT delorie DOT com Precedence: bulk On Tue, 18 Dec 2012, David C. Kerber wrote: > > >> -----Original Message----- >> From: gedau AT igor2 DOT repo DOT hu [mailto:gedau AT igor2 DOT repo DOT hu] >> Sent: Tuesday, December 18, 2012 4:28 AM >> To: geda-user AT delorie DOT com >> Subject: Re: [geda-user] Find rat lines - summary >> >> >> >> On Tue, 18 Dec 2012, Russell Dill wrote: >> >>>> Wheter it's highlighting or drawing an extra rubber band >> line doesn't make >>>> much difference as too much of the existing copper would be marked. >>> >>> Let me try to be more clear, I'm not talking about highlighting or >>> marking copper, I'm just talking about drawing an ant trail. >>> >> >> Clear. The problem is _where_ you draw it. If you draw it >> over all the >> copper of both nets, it's not very useful; if you draw it between all >> pins of the two nets, it's not very useful either. Can you please >> describe where would you draw it in the H example (net1=a,b net2=C,D): >> >> a --+-- b >> | >> C --+-- D > > It's clear to me that he means to draw the line from any one single pin on net 1 to any one single pin on net 2. So for your case, it would draw from A->C, or A->D, or B->C or B->D, but only ONE of those 4 possible paths. Once you trace that single route, you will find where the short is. Or if there is more than one short, this will allow you to find them one at a time. > Thanx, I missed the important point of drawing only one of the paths, making the process iterative. This is an approach different from those that have been proposed so far so I am addig it on the proposals summary in svn as II/6.