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Date:	Sat, 11 Dec 2004 18:36:49 +0200
From:	"Eli Zaretskii" <eliz AT gnu DOT org>
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To:	djgpp AT delorie DOT com
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In-reply-to:	<gTDud.16862$Lg7.531795@twister1.libero.it> (message from Carlo
	on Sat, 11 Dec 2004 14:55:08 GMT)
Subject:	Re: why inportb and outportb are so time expensive ?
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> From: Carlo <mail AT bo DOT uf>
> Date: Sat, 11 Dec 2004 14:55:08 GMT
> 
> My application runs on a dos machine (MS-Dos 6.0) with a i386sx 
> processor @ 33 Mhz clock, with cwsdpmi r5.
> One program loop takes about 1 mSec, 75% of this millisecond spent for 
> inportb and outportb (with an average of 30/40 calls to that functions). 
> Without any of these calls the program runs up to 10 times faster.

Like DJ said: make sure you are compiling with optimizations to get
the in/outportb functions inlined, then compare the results (e.g., 20
microseconds per call if the results above are still valid) with the
speed of your bus (for 33MHz clock, it's usually 8MHz, but there could
be wait states) and the speed of the hardware you are reading and
writing to.

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