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From: | Martin Ambuhl <mambuhl AT earthlink DOT net> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: function question |
Date: | Sun, 04 Apr 2004 17:27:37 -0400 |
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Bill Cunningham wrote: > I don't know if it would be better to post this here or comp.lang.c but > I'll post it here since it's djgpp specific. If it were djgpp-specific, it is obvious that it goes to comp.os.msdos.djgpp, not to comp.lang.c, where compiler-specific questions are off-topic. However, your question has nothing to do with djgpp, but with basic, elementary C. >I'm working on some open source > programming and seem to have run up against a wall. Can anyone give me any > pointers(no pun intended) on this. > > int ma (int np[]) > {puts("This is number of prices? -> "); > fflush(stdout); > puts(int *(np));} > > What this function is supossed to do is accept input of a number of prices > an investor wants to include in a simple moving average. Hince the ma. The > int * cast is the last thing to my knowledge to try. I know workable C. I'm > not really experienced with the fancy ins and outs. As the funcion > continues, it should tally a number of prices and calculate a ma. Then I'll > include it into a static library where it can be linked with a file > containing main(). 'int *' is not a cast; it's a syntax error. With a cast, the line puts((int *)np); makes no sense, and the cast is superfluous as well. Your argument list suggests that np is an array, with the "code" suggesting np[0] holds the value you want. This is probably not true. int ma(int *np) { printf("This is number of prices? -> %d\n", *np); return *np; /* ? */ } C is really easy if you bother to learn it before coding.
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