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From: | "Campbell, Rolf [SKY:1U32:EXCH]" <cp1v45 AT americasm01 DOT nt DOT com> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: From Bytes to Int and Char |
Date: | Fri, 13 Aug 1999 14:41:27 -0400 |
Organization: | Nortel Networks |
Lines: | 21 |
Message-ID: | <37B466D7.958F09E5@americasm01.nt.com> |
References: | <rfXs3.4$bZ1 DOT 1603 AT typhoon01 DOT swbell DOT net> |
NNTP-Posting-Host: | bmerhc00.ca.nortel.com |
Mime-Version: | 1.0 |
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To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
Nick wrote: > I am trying to load some data from a files, the 6 and 7th bytes are an > Integer and so are the 11th and 12th. How do I make them into an INT? This > is what I used earlier > > char ver, type; > int sz, tz; > > sz = file_buffer[6] + file_buffer[7]; > is that right? No. Here's the right way to do it. This code is not edian safe. sz = *(short*)(file_buffer+6); -- -Rolf Campbell (39)3-6318
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