Mail Archives: djgpp/1997/10/16/16:25:00
Nate Eldredge <eldredge AT ap DOT net> wrote:
> At 04:32 10/15/1997 +0000, Salvador Eduardo Tropea (SET) wrote:
> >Eli Zaretskii <eliz AT is DOT elta DOT co DOT il> wrote:
>
> >> However, I think I have a case where the link order really is
> >> important. This is when one or more of the modules being linked use
> >> functions with `__attribute__((constructor))' or ((destructor)).
> >>
> >> For example, imagine that a program uses Filesystem Extensions to
> >> install handlers for some special files, and uses the constructor
> >> attribute to make the installation happen before `main' gets called.
> >>
> >> These functions will be invoked by the startup/exit code in the order
> >> they are seen by the linker. And that order might be important,
> >> e.g. when one function needs to install itself ahead of others, so it
> >> sees the calls first.
> >I faced this problem with constructors of classes and library functions that
> >must be initialized before the constructor. I think the best way is to call
> the
> >initialization of the other module from the constructor.
************************************
> >If the module is
> >already initialized it will return without making anything, if not is
> >initialized. The other way is to check if the module is initialized in each
> >function that's called externally. The last is a good practice and normally
> >isn't slow to add:
> >
> >XXXX
> >{
> > if (!initialized)
> > initialize();
> >}
> >
> >in the entry points. In this way you don't depend on the order of the link.
> Or how about this:
> void initialize(void) __attribute__((constructor));
>
> void initialize(void)
> {
> initialize_first_piece();
> initialize_second_piece();
> /* ... */
> }
>
Of course is valid, is the same I say above the ****************** ;-)
SET
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